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Quora for JEE Mains and NEET: Study Rate Community

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  1. Asked: February 29, 2024In: JEE Mains

    In Bohr’s model of an atom which of the following is an integral multiple of h/2π?

    Parul Singla
    Best Answer
    Parul Singla Teacher
    Added an answer on February 29, 2024 at 1:29 pm

    Answer:D)-Angular momentum Explaination:(d) Angular momentum L = mvr = nh/2π

    Answer:D)-Angular momentum

    Explaination:(d) Angular momentum L = mvr = nh/2π

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  2. Asked: February 28, 2024In: Class 8

    The equation 2x + 5y = 7 has a unique solution, if x and y are

    Community
    Best Answer
    Community Beginner
    Added an answer on February 28, 2024 at 7:21 am

    Solution: Since, every point on the line represented by the equation 2x + 5y = 7 is its solution. Therefore, there are infinite solutions of the equation the equation 2x + 5y = 7 in which the values of x and y are rational numbers, positive real numbers or real numbers. But, as 2 + 5 = 7, i.e. x = 1Read more

    Solution:

    Since, every point on the line represented by the equation 2x + 5y = 7 is its solution.

    Therefore, there are infinite solutions of the equation the equation 2x + 5y = 7 in which the values of x and y are rational numbers, positive real numbers or real numbers.

    But, as 2 + 5 = 7, i.e. x = 1 and y = 1 are the only pair of natural numbers that are the solution of the equation equation 2x + 5y = 7.

    So, the equation 2x + 5y = 7 has a unique solution, if x and y are both natural numbers.

    Hence, the correct option is (a).

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  3. Asked: February 28, 2024In: JEE Mains

    What are the hydrolysis products of

    Community
    Best Answer
    Community Beginner
    Added an answer on February 28, 2024 at 6:51 am

    Solution: (i) On hydrolysis, sucrose gives one molecule of ∝-D glucose and one molecule of β- D-fructose. (ii) The hydrolysis of lactose gives β-D-galactose and β-D-glucose.

    Solution:

    (i) On hydrolysis, sucrose gives one molecule of ∝-D glucose and one molecule of β– D-fructose.

    (ii) The hydrolysis of lactose gives β-D-galactose and β-D-glucose.

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  4. Asked: February 28, 2024In: Class 11

    State two economically important uses of:

    Community
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    Community Beginner
    Added an answer on February 28, 2024 at 6:17 am

    Economically important uses of microorganisms: a) Heterotrophic bacteria: Food production: Fermentation: Heterotrophic bacteria are used in the fermentation of various food products like yogurt, cheese, bread, and sauerkraut. These bacteria break down sugars and other organic compounds, producing laRead more

    Economically important uses of microorganisms:

    a) Heterotrophic bacteria:

    1. Food production:

      • Fermentation: Heterotrophic bacteria are used in the fermentation of various food products like yogurt, cheese, bread, and sauerkraut. These bacteria break down sugars and other organic compounds, producing lactic acid, alcohol, and other byproducts that contribute to the taste, texture, and preservation of the food.
      • Single-cell protein: Some heterotrophic bacteria can be grown on a large scale as a source of protein for animal feed or even human consumption. This is seen as a potentially sustainable way to meet the growing demand for protein.
    2. Biotechnology:

      • Production of chemicals and enzymes: Heterotrophic bacteria are used to produce a variety of chemicals and enzymes that are used in various industries. These include antibiotics, vitamins, organic acids, and industrial enzymes used in the production of detergents, textiles, and biofuels.

    b) Archaebacteria:

    1. Biogas production:

      • Methanogens: These archaea are used in the process of anaerobic digestion, which breaks down organic matter in the absence of oxygen and produces biogas. Biogas is a renewable energy source that can be used for cooking, heating, and electricity generation.
    2. Bioremediation:

      • Halophiles: These archaea can thrive in salty environments and are used to clean up oil spills in the ocean. They break down the hydrocarbons in the oil, helping to remove them from the environment.

    These are just a few examples of the many economically important uses of heterotrophic bacteria and archaebacteria. These microorganisms play a vital role in various industries and contribute significantly to our daily lives.

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  5. Asked: February 19, 2024In: JEE Mains

    The phenolic group can be identified by a positive result by which of the following tests?

    Community
    Best Answer
    Community Beginner
    Added an answer on February 19, 2024 at 3:54 pm

    The phenolic group can be identified by a positive result in the Phthalein test. The Phthalein test is specific for detecting the presence of phenolic groups. In this test, phenols react with phthalic anhydride in the presence of concentrated sulfuric acid to form a colored compound. This reaction iRead more

    The phenolic group can be identified by a positive result in the Phthalein test.

    The Phthalein test is specific for detecting the presence of phenolic groups. In this test, phenols react with phthalic anhydride in the presence of concentrated sulfuric acid to form a colored compound. This reaction is specific to phenolic groups, making the Phthalein test a suitable method for their identification.

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  6. Asked: February 19, 2024In: JEE Mains

    Which of the following can not act as an oxidising agent?

    iresh
    Best Answer
    iresh Beginner
    Added an answer on February 19, 2024 at 3:50 pm

    Of the options provided, the one that cannot act as an oxidizing agent is ii. SO42-. Sure! SO42- cannot act as an oxidizing agent because it is already in its highest oxidation state (+6) in the sulfate ion (SO42-). To act as an oxidizing agent, a species needs to be able to undergo reduction itselfRead more

    Of the options provided, the one that cannot act as an oxidizing agent is ii. SO42-.

    Sure! SO42- cannot act as an oxidizing agent because it is already in its highest oxidation state (+6) in the sulfate ion (SO42-). To act as an oxidizing agent, a species needs to be able to undergo reduction itself, meaning it must have the potential to lose electrons. Since sulfur in the sulfate ion is already at its highest possible oxidation state, it cannot lose any more electrons and, therefore, cannot act as an oxidizing agent.

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