The electronic configuration of Neodymium (\(60\) Nd) is:
(a) \([Xe] 4f^{4} 6s^{2}\)
(b) \([Xe] 5f^{1}\)
(c) \([Xe] 4f^{2} 6s^{2}\)
(d) \([Xe] 5f^{4} 4d^{1}\)
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The electronic configuration of Neodymium (60) Nd is
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Neodymium (\(60\) Nd) belongs to the lanthanide series and has an atomic number of \(60\). The electronic configuration of neodymium can be determined by referring to the periodic table.
The electronic configuration of Neodymium (\(60\) Nd) is typically represented as:
(a) \([Xe] 4f^{4} 6s^{2}\)
This configuration accounts for the filling of electrons in the \(4f\) and \(6s\) orbitals after the noble gas configuration of xenon (\([Xe]\)).
Therefore, the correct answer is option (a).