Class 11 Physics Case Study Questions Chapter 6 Work, Energy, and Power

In Class 11 Final Exams there will be Case studies and Passage Based Questions will be asked, So practice these types of questions. Study Rate is always there to help you. Free PDF Downloads of CBSE Class 11 Physics Chapter 6 Case Study and Passage-Based Questions with Answers were Prepared Based on the Latest Exam Pattern. Students can solve Class 11 Physics Case Study Questions Work, Energy, and Power to know their preparation level.

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In CBSE Class 11 Physics Paper, There will be a few questions based on case studies and passage-based as well. In that, a paragraph will be given, and then the MCQ questions based on it will be asked.

Work, Energy, and Power Case Study Questions With Answers

Here, we have provided case-based/passage-based questions for Class 11 Physics Chapter 6 Work, Energy, and Power

Case Study/Passage-Based Questions

Case Study 1: The kinetic energy possessed by an object of mass, m, and moving with a uniform velocity, v is

Kinetic energy is a scalar quantity. The kinetic energy of an object is a measure of the work and The energy possessed by an object is thus measured in terms of its capacity of doing work. The unit of energy is, therefore, the same as that of work, that is, joule (J).

Work energy theorem: The change in kinetic energy of a particle is equal to the work done on it by the net force. Mathematically

Kf – Ki = W

Where Kand Kf are respectively the initial and final kinetic energies of the object. Work refers to the force and the displacement over which it acts. Work is done by a force on the body over a certain displacement.

1) Kinetic energy is

  • a) Scalar quantity
  • b) Vector quantity
  • c) None of these

Answer: a) Scalar quantity


2) Which of the following has the same unit?

  • a) Potential energy and work
  • b) Kinetic energy and work
  • c) Force and weight
  • d) All of the above

Answer: d) All of the above


3) A car with an initial kinetic energy of 400 J is brought to a stop by applying brakes. How much work is done by the brakes?
a) -400 J
b) 0 J
c) 400 J
d) 800 J

Answer: a) -400 J


4) What happens to the kinetic energy of an object if its velocity is doubled?
a) It remains the same.
b) It becomes four times.
c) It becomes half.
d) It becomes twice.

Answer: b) It becomes four times.


5) According to the work-energy theorem, if a body’s kinetic energy decreases, the work done by the net force must be:
a) Positive
b) Negative
c) Zero
d) Infinite

Answer: b) Negative


What is the kinetic energy of an object with a mass of 10 kg and a velocity of 5 m/s?
a) 125 J
b) 250 J
c) 500 J
d) 50 J

Answer: a) 125 J


Case Study 2: The work-energy theorem states that – the change in the kinetic energy of a body is equal to the work done by the net force. In deriving the theorem, it is assumed that force is effective only in changing the KE. When the force and displacement are in the same direction, KE increases and work done is positive. When the force and displacement are in opposite directions, KE decreases and work done is negative. When the body is in uniform motion, KE does not change and work done by centripetal force is zero.

(i) A body of mass 10 kg initially at rest, acquires a velocity of 10 m/s. The work done is:
(a) -500J (b) 500J (c) 50J (d) – 50J

Answer: (a) -500J


(ii) How much work must be done by a force on a 50 kg body in order to accelerate from rest to 20
m/s in 10 sec?

(a) 103 J (b) 104 J (c) 2 X 103 J
(d) 4 X 104 J

Answer: (b) 104 J


(iii) A gun of mass M fires a bullet of mass m with maximum speed v. The KE of gun will be?
(a) ½ mv2 (b) 1/2 Mv2
(c) more than ½ mv2
(d) less than½ mv2

Answer: (d) less than½ mv2


(iv) An unloaded car moving with velocity v on a frictionless road can be stopped in a distance s.
If the passengers add 40% to its weight and the breaking force remains the same then the stopping
distance will be:
(a) 1.4 s (b) 1.5 s (c) 1.6 s (d) 1.8 s

Answer: (a) 1.4 s


(v) A block of mass 10 kg is moving in the x direction with a constant speed of 10 m/s. It is subjected
to a retarding force F = – 0.1 xj/m during its travel from x=20m to x=30m. Final KE will be

(a) 250J (b) 275J (c) 450J (d) 475J

Answer: (d) 475J


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