50+ JEE Mains MCQ Questions Aldehydes Ketones and Carboxylic Acids with Solutions

Preparing for the Joint Entrance Exam (JEE) can be a daunting task. With so many subjects to cover and so many topics to study, it can be challenging to know where to start. One essential topic in the JEE Mains syllabus is the Aldehydes, Ketones and Carboxylic Acids. In this article, we will provide 50+ MCQ questions on the Aldehydes, Ketones and Carboxylic Acids, along with detailed solutions to help you prepare for the JEE Mains exam.

These 50+ MCQ questions are selected by the experts of studyrate.in and these are more difficult questions, which will help you to better understand Aldehydes, Ketones and Carboxylic Acids JEE Mains MCQ Questions with Answers.

Aldehydes, Ketones and Carboxylic Acids JEE Mains MCQ


Which of the following compounds can act as both an aldehyde and a ketone?
a) Acetaldehyde
b) Formaldehyde
c) Acetone
d) Benzaldehyde

Answer: c) Acetone Explanation: Acetone (CH3COCH3) can act as both an aldehyde and a ketone because it contains a carbonyl group (C=O) attached to two carbon atoms.

The IUPAC name of the compound CH3COCH2CH3 is:
a) Propanal
b) Propanone
c) Propanoic acid
d) Propanoate

Answer: b) Propanone Explanation: CH3COCH2CH3 is propanone, which is the IUPAC name for the compound commonly known as acetone.

The reaction of aldehydes with NaBH4 leads to the formation of:
a) Alcohols
b) Ketones
c) Carboxylic acids
d) Esters

Answer: a) Alcohols Explanation: The reaction of aldehydes with sodium borohydride (NaBH4) is a reduction reaction that converts aldehydes to alcohols.

Which of the following compounds undergoes oxidation to form a carboxylic acid?
a) Aldehyde
b) Ketone
c) Ester
d) Amide

Answer: a) Aldehyde Explanation: Aldehydes can be oxidized to form carboxylic acids.

The compound CH3COOH is an example of a:
a) Ketone
b) Aldehyde
c) Carboxylic acid
d) Ester

Answer: c) Carboxylic acid Explanation: CH3COOH is acetic acid, which is a carboxylic acid.

The compound CH3CH2CHO is commonly known as:
a) Ethanal
b) Acetone
c) Propionaldehyde
d) Butanone

Answer: c) Propionaldehyde Explanation: CH3CH2CHO is propionaldehyde, which is an aldehyde compound.

The reaction of a ketone with NaBH4 leads to the formation of:
a) Alcohols
b) Aldehydes
c) Carboxylic acids
d) Esters

Answer: a) Alcohols Explanation: The reaction of ketones with sodium borohydride (NaBH4) is a reduction reaction that converts ketones to alcohols.

The compound CH3COCH2COOH is an example of a:
a) Ketone
b) Aldehyde
c) Carboxylic acid
d) Ester

Answer: c) Carboxylic acid Explanation: CH3COCH2COOH is oxalic acid, which is a carboxylic acid.

The reaction of carboxylic acids with alcohols in the presence of a strong acid catalyst forms:
a) Aldehydes
b) Ketones
c) Esters
d) Amides

Answer: c) Esters Explanation: The reaction of carboxylic acids with alcohols in the presence of a strong acid catalyst forms esters.

The compound CH3COCl is commonly known as:
a) Acetic acid
b) Acetone
c) Acetyl chloride
d) Acetamide

Answer: c) Acetyl chloride Explanation: CH3COCl is acetyl chloride, which is an acyl chloride compound.


Which of the following compounds undergoes Cannizzaro reaction?
a) Acetone
b) Benzaldehyde
c) Acetaldehyde
d) Acetophenone

Answer: b) Benzaldehyde Explanation: The Cannizzaro reaction involves the self-oxidation and reduction of aldehydes that do not have an α-hydrogen. Benzaldehyde undergoes the Cannizzaro reaction.

The reaction of an aldehyde with Tollens’ reagent results in the formation of:
a) A carboxylic acid
b) An alcohol
c) An aldehyde
d) A ketone

Answer: d) A ketone Explanation: Tollens’ reagent (ammoniacal silver nitrate) oxidizes aldehydes to form a silver mirror and the corresponding carboxylic acid, but in the absence of heat, it forms a ketone.

The compound CH3CHO is commonly known as:
a) Acetone
b) Acetaldehyde
c) Acetic acid
d) Formic acid

Answer: b) Acetaldehyde Explanation: CH3CHO is acetaldehyde, which is a common aldehyde compound.

The reaction of a carboxylic acid with an alcohol in the presence of an acid catalyst forms:
a) An ester
b) An aldehyde
c) A ketone
d) An amide

Answer: a) An ester Explanation: The reaction of a carboxylic acid with an alcohol in the presence of an acid catalyst, known as esterification, forms an ester.

The IUPAC name of the compound CH3COCH(CH3)2 is:
a) Propanal
b) Propanone
c) 2-Propanol
d) 2-Methylpropanal

Answer: b) Propanone Explanation: CH3COCH(CH3)2 is propanone, also known as acetone, which is the IUPAC name for this compound.

The compound CH3CH2COOH is an example of a:
a) Ketone
b) Aldehyde
c) Carboxylic acid
d) Ester

Answer: c) Carboxylic acid Explanation: CH3CH2COOH is propanoic acid, which is a carboxylic acid.

The compound CH3C(O)CH2CH2C(O)CH3 is an example of a:
a) Ketone
b) Aldehyde
c) Carboxylic acid
d) Ester

Answer: a) Ketone Explanation: CH3C(O)CH2CH2C(O)CH3 is a ketone compound. It has two carbonyl groups (-C=O) attached to carbon atoms.

The reaction of aldehydes with ammonia and its derivatives forms:
a) Carboxylic acids
b) Amines
c) Ketones
d) Esters

Answer: b) Amines Explanation: The reaction of aldehydes with ammonia (NH3) or its derivatives (such as primary amines) forms amines through nucleophilic addition reactions.

The compound CH3COCl is commonly known as:
a) Acetone
b) Acetaldehyde
c) Acetyl chloride
d) Acetamide

Answer: c) Acetyl chloride Explanation: CH3COCl is acetyl chloride, which is an acyl chloride compound.

Which of the following reagents is used for the oxidation of primary alcohols to aldehydes?
a) Chromic acid (H2CrO4)
b) KMnO4
c) Jones reagent (CrO3 + H2SO4)
d) PCC (pyridinium chlorochromate)

Answer: d) PCC (pyridinium chlorochromate) Explanation: PCC is commonly used for the selective oxidation of primary alcohols to aldehydes.


Which of the following compounds is formed when acetaldehyde reacts with excess alcohol in the presence of an acid catalyst?
a) Acetone
b) Diethyl acetal
c) Acetic acid
d) Acetophenone

Answer: b) Diethyl acetal Explanation: Acetaldehyde reacts with excess alcohol in the presence of an acid catalyst to form diethyl acetal.

The reaction of a carboxylic acid with an alcohol in the presence of a mineral acid catalyst forms:
a) An ester
b) An aldehyde
c) A ketone
d) An amide

Answer: a) An ester Explanation: The reaction of a carboxylic acid with an alcohol in the presence of a mineral acid catalyst forms an ester through esterification.

The compound CH3COOCH3 is commonly known as:
a) Acetone
b) Methyl acetate
c) Acetic acid
d) Ethyl acetate

Answer: b) Methyl acetate Explanation: CH3COOCH3 is methyl acetate, which is an ester compound.

The reaction of a ketone with sodium nitroprusside in the presence of ammonia gives a positive test for the presence of:
a) Aldehydes
b) Ketones
c) Carboxylic acids
d) Amines

Answer: a) Aldehydes Explanation: The reaction of a ketone with sodium nitroprusside in the presence of ammonia gives a positive test for the presence of aldehydes, known as the Tollens’ test.

The compound CH3COCH(CH3)COOH is an example of a:
a) Ketone
b) Aldehyde
c) Carboxylic acid
d) Ester

Answer: c) Carboxylic acid Explanation: CH3COCH(CH3)COOH is a carboxylic acid compound called 3-oxobutanoic acid.

The reaction of a carboxylic acid with an amine in the presence of heat forms:
a) An ester
b) An amide
c) An aldehyde
d) A ketone

Answer: b) An amide Explanation: The reaction of a carboxylic acid with an amine in the presence of heat forms an amide.

The IUPAC name of the compound CH3CH2CHO is:
a) Propanal
b) Propanone
c) Propanoic acid
d) Propanoate

Answer: a) Propanal Explanation: CH3CH2CHO is propanal, which is the IUPAC name for this compound.

Which of the following compounds is used as a reducing agent in the Wolff-Kishner reaction?
a) Sodium borohydride (NaBH4)
b) Lithium aluminum hydride (LiAlH4)
c) Hydrazine (N2H4)
d) Sodium amalgam (Na/Hg)

Answer: c) Hydrazine (N2H4) Explanation: Hydrazine (N2H4) is used as a reducing agent in the Wolff-Kishner reaction to convert carbonyl compounds into corresponding hydrocarbons.

The compound CH3CHO is commonly known as:
a) Acetone
b) Acetaldehyde
c) Acetic acid
d) Formaldehyde

Answer: b) Acetaldehyde Explanation: CH3CHO is acetaldehyde, which is a common aldehyde compound.

The reaction of an aldehyde with a primary amine forms:
a) A carboxylic acid
b) An amide
c) An aldehyde
d) A ketone

Answer: b) An amide Explanation: The reaction of an aldehyde with a primary amine forms an amide through nucleophilic addition reactions.

We hope there JEE MCQ of Class 12 Aldehydes, Ketones and Carboxylic Acids will help you to score an excellent rank in JEE Mains and Advanced. If you have any queries feel free to write in the comments section. We at Study Rate are always ready to serve our students.

Sneha

Master's in Biology, Skilled in vocational training. Strong Analytical and creative knowledge.

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