50+ NEET MCQ Questions Oscillations with Solutions

Here we will provide you the 50+ MCQ Questions of Oscillations for NEET-UG. Oscillations is the chapter 14 in Class XI or Class 11 Physics NCERT Unit Oscillations NEET (conducted by NTA) is based on the NCERT book.

These 50+ MCQ questions are selected by the experts of studyrate.in and these are more difficult questions, which will help you to better understand Oscillations NEET MCQ Questions with Answers.

Oscillations NEET MCQ


A spring-mass system is set into simple harmonic motion by applying an external force F = F0 cos(ωt). The maximum kinetic energy of the mass is:
A) F0^2/(2mω^2)
B) F0^2/(4mω^2)
C) F0^2/(8mω^2)
D) F0^2/(16mω^2)

Answer: B) F0^2/(4mω^2)

A block of mass M hangs from a massless spring with spring constant k. The mass is displaced from its equilibrium position by a small distance x and then released. The frequency of the resulting simple harmonic motion is given by:
A) f = (1/2π)√(k/M)
B) f = (1/π)√(k/M)
C) f = (1/2π)√(M/k)
D) f = (1/π)√(M/k)

Answer: D) f = (1/π)√(M/k)

Two simple harmonic oscillations of angular frequencies ω1 and ω2, and amplitudes A1 and A2 respectively, are combined such that their displacement at any instant is given by y = A1 sin(ω1t) + A2 sin(ω2t). The amplitude of the resultant oscillation is given by:
A) √(A1^2 + A2^2)
B) √(2A1^2 + 2A2^2)
C) √(A1^2 + A2^2 + 2A1A2 cos(Δωt))
D) √(A1^2 + A2^2 – 2A1A2 cos(Δωt))

Answer: C) √(A1^2 + A2^2 + 2A1A2 cos(Δωt)), where Δω = |ω1 – ω2|

A simple pendulum of length L and mass m has a period T. If the length of the pendulum is doubled and the mass is tripled, the new period will be:
A) T
B) 2T
C) 3T
D) 6T

Answer: A) T

A massless spring with spring constant k is attached to a block of mass m and to a wall. The block is displaced from its equilibrium position by a small distance x and then released. The maximum speed of the block during the subsequent simple harmonic motion is:
A) √(kx^2/m)
B) √(2kx^2/m)
C) √(3kx^2/m)
D) √(4kx^2/m)

Answer: B) √(2kx^2/m)


A particle executing SHM has a maximum speed of v and a maximum acceleration of a. The ratio of maximum potential energy to the maximum kinetic energy is
a) 1 : 1
b) a/v
c) v/a
d) a²/v²

Answer: d) a²/v²

A mass of 0.2 kg hangs vertically from a spring of force constant 1000 N/m. The frequency of oscillations is
a) 10 Hz
b) 14 Hz
c) 16 Hz
d) 20 Hz

Answer: b) 14 Hz

A simple pendulum of length 1.5 m and mass 2 kg is displaced through an angle of 10° and then released. The velocity of the bob when it passes through its lowest point is
a) 0.5 m/s
b) 1 m/s
c) 1.5 m/s
d) 2 m/s

Answer: c) 1.5 m/s

Two simple pendulums of lengths 1 m and 4 m respectively have the same time period. If the length of the third pendulum, which has the same time period, is k times that of the first pendulum, then the value of k is
a) 4
b) 16
c) 64
d) 256

Answer: c) 64

A block of mass 2 kg is attached to a spring of force constant 50 N/m and is executing SHM on a frictionless surface. The amplitude of the motion is 0.1 m. The maximum kinetic energy of the block is
a) 0.5 J
b) 1 J
c) 1.5 J
d) 2 J

Answer: c) 1.5 J

The time period of oscillation of a simple pendulum is T. Its length is increased by 50%. The new time period of oscillation will be
a) 2T
b) T/2
c) T(√3)/2
d) T(√2)/2

Answer: c) T(√3)/2

Two simple pendulums A and B have lengths 1 m and 4 m respectively. They are given small oscillations simultaneously. If the time period of the first pendulum is 2 seconds, then the time after which the two pendulums will again have their maximum displacement in the same direction is
a) 16 seconds
b) 8 seconds
c) 4 seconds
d) 2 seconds

Answer: a) 16 seconds

A spring block system has a time period of 2 seconds. The time period of the same system with half the mass and double the force constant will be
a) 1/√2 seconds
b) 1 second
c) 2/√2 seconds
d) 2 seconds

Answer: a) 1/√2 seconds

A particle executing SHM takes t1 and t2 seconds to travel from its equilibrium position to the maximum displacement and from the maximum displacement to the equilibrium position respectively. The time period of the motion is
a) t1 + t2
b) t1 – t2
c) t1 × t2
d) √(t1t2)

Answer: d) √(t1t2)


Which of the following is an example of a damped oscillation?
a) a simple pendulum
b) a mass on a spring
c) a tuning fork
d) a bouncing ball

Answer: d) a bouncing ball

In simple harmonic motion, the acceleration of the oscillating object is
a) proportional to its displacement
b) proportional to its velocity
c) proportional to the square of its displacement
d) proportional to the square of its velocity

Answer: a) proportional to its displacement

A block of mass m is attached to a spring of spring constant k. If the mass is displaced by x from its equilibrium position and released, what is the frequency of the resulting oscillation?
a) 2π√(k/m)
b) √(k/m)
c) 1/(2π√(k/m))
d) (2π√(k/m))/x

Answer: a) 2π√(k/m)

The displacement of a particle undergoing simple harmonic motion is given by x = 3 sin (4t + π/3) where x is in meters and t is in seconds. What is the amplitude of the oscillation?
a) 4
b) 3
c) 2
d) 1

Answer: b) 3

An object of mass m is attached to a spring of spring constant k and set into oscillation with amplitude A. What is the maximum kinetic energy of the object during the oscillation?
a) (1/2)kA^2
b) (1/2)k^2A^2/m
c) (1/2)mv^2
d) (1/2)kA/m

Answer: d) (1/2)kA^2


A simple pendulum has a time period T. If its length is increased by 21% and the amplitude is increased by 50%, the new time period will be:
a. 1.62 T
b. 1.50 T
c. 1.26 T
d. 1.12 T

Answer: c. 1.26 T

A block of mass m is attached to a spring of spring constant k. The block oscillates on a horizontal frictionless surface with an amplitude A. If the maximum kinetic energy of the block is K, the potential energy stored in the spring when the block is at the equilibrium position is:
a. K/4
b. K/2
c. K
d. 2K

Answer: b. K/2

A simple pendulum is suspended from the ceiling of an elevator that is moving upward with a constant acceleration a. The time period of the pendulum in the elevator is T. If the elevator is moving downward with the same acceleration a, the time period of the pendulum will be:
a. T(1 + a/g)
b. T(1 – a/g)
c. T(1 – a^2/g^2)
d. T(1 + a^2/g^2)

Answer: b. T(1 – a/g)

A mass m is attached to a spring of spring constant k and the system is executing simple harmonic motion. The amplitude of the motion is A. What is the maximum speed of the mass?
a. A(2k/m)^1/2
b. A(k/m)^1/2
c. A(g/k)^1/2
d. A(k/g)^1/2

Answer: a. A(2k/m)^1/2

A body of mass m is attached to a spring of spring constant k and is executing simple harmonic motion with a frequency f. If the mass is increased by a factor of 2 and the spring constant is decreased by a factor of 2, the frequency of the motion will be:
a. f/2
b. f
c. 2f
d. 4f

Answer: b. f

We hope there NEET MCQ of Class 11 Oscillations will help you to score an excellent rank in NEET-UG. If you have any queries feel free to write in the comments section. We at Study Rate are always ready to serve our students

Sneha

Master's in Biology, Skilled in vocational training. Strong Analytical and creative knowledge.

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