Preparing for the Joint Entrance Exam (JEE) can be a daunting task. With so many subjects to cover and so many topics to study, it can be challenging to know where to start. One essential topic in the JEE Mains syllabus is the Electrostatic Potential and Capacitance. In this article, we will provide 50+ MCQ questions on the Electrostatic Potential and Capacitance, along with detailed solutions to help you prepare for the JEE Mains exam.
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These 50+ MCQ questions are selected by the experts of studyrate.in and these are more difficult questions, which will help you to better understand Electrostatic Potential and Capacitance JEE Mains MCQ Questions with Answers.
Electrostatic Potential and Capacitance JEE Mains MCQ
The electrostatic potential at a point is defined as the:
a) Work done in bringing a unit positive charge from infinity to that point
b) Electric field at that point
c) Charge at that point
d) Voltage at that point
The SI unit of electric potential is the:
a) Volt
b) Ampere
c) Coulomb
d) Ohm
The electric potential difference between two points in an electric field is also called:
a) Electric field strength
b) Electric force
c) Electric potential energy
d) Electric flux
The potential difference between two points is 12 V. The work done in moving a charge of 2 C between these points is:
a) 12 J
b) 24 J
c) 6 J
d) 0 J
The potential due to a point charge varies with distance as:
a) Directly proportional to the distance
b) Inversely proportional to the distance
c) Inversely proportional to the square of the distance
d) None of the above
The electric potential at the surface of a charged conductor is:
a) Maximum
b) Minimum
c) Zero
d) Cannot be determined
The electric potential inside a conductor in electrostatic equilibrium is:
a) Zero
b) Non-zero
c) Maximum at the surface of the conductor
d) Maximum inside the conductor
The equipotential surfaces are always:
a) Parallel to each other
b) Perpendicular to each other
c) Concentric spheres around a point charge
d) All of the above
The work done in moving a test charge along an equipotential surface is:
a) Zero
b) Non-zero
c) Depends on the charge of the test charge
d) Depends on the shape of the equipotential surface
The capacitance of a capacitor depends on:
a) The area of the plates
b) The distance between the plates
c) The dielectric constant of the material between the plates
d) All of the above
The SI unit of capacitance is the:
a) Farad
b) Ohm
c) Volt
d) Ampere
The capacitance of a parallel-plate capacitor is given by:
a) C = Q/V
b) C = V/Q
c) C = Qd/V
d) C = ε₀A/d
The energy stored in a capacitor is given by:
a) U = 1/2CV²
b) U = 1/2QV
c) U = 1/2Q²/C
d) U = 1/2CV
The dielectric constant of a material is a measure of its:
a) Conductivity
b) Permittivity
c) Resistance
d) Capacitance
When a dielectric material is inserted between the plates of a capacitor, the capacitance:
a) Increases
b) Decreases
c) Remains the same
d) Depends on the voltage applied
The phenomenon of dielectric breakdown occurs when:
a) The voltage across a capacitor exceeds its maximum limit
b) The dielectric material between the plates of a capacitor breaks down due to excessive electric field
c) The capacitor discharges all its stored energy suddenly
d) None of the above
The combination of capacitors in series has:
a) The same capacitance as the individual capacitors
b) A smaller capacitance than the individual capacitors
c) A larger capacitance than the individual capacitors
d) None of the above
The combination of capacitors in parallel has:
a) The same capacitance as the individual capacitors
b) A smaller capacitance than the individual capacitors
c) A larger capacitance than the individual capacitors
d) None of the above
The equivalent capacitance of two capacitors in series can be calculated as:
a) 1/C = 1/C₁ + 1/C₂
b) C = C₁ + C₂
c) C = C₁C₂
d) C = C₁ – C₂
The equivalent capacitance of two capacitors in parallel can be calculated as:
a) C = C₁ + C₂
b) C = C₁C₂
c) 1/C = 1/C₁ + 1/C₂
d) C = C₁ – C₂
The energy stored in a capacitor is given by the formula:
a) U = 1/2CV²
b) U = CV²
c) U = 1/2C²V
d) U = C/V²
The electric field inside a parallel-plate capacitor is:
a) Zero
b) Non-zero
c) Maximum at the center of the capacitor
d) Maximum at the edges of the capacitor
The charge on a capacitor is given by the formula:
a) Q = CV
b) Q = C/V
c) Q = C²/V
d) Q = V/C
The voltage across a capacitor is given by the formula:
a) V = Q/C
b) V = C/Q
c) V = Q²/C
d) V = C/Q²
We hope there JEE MCQ of Class 12 Electrostatic Potential and Capacitance will help you to score an excellent rank in JEE Mains and Advanced. If you have any queries feel free to write in the comments section. We at Study Rate are always ready to serve our students.
