MCQ Quiz on Class 11 Maths Chapter 12 Introduction to Three Dimensional Geometry with Answers

We have compiled the MCQ Questions for Class 11 Maths Chapter 12 Introduction to Three Dimensional Geometry with Answers Pdf free download covering the entire syllabus for JEE and Boards. Practice MCQ Questions for Class 11 Maths with Answers on a daily basis and score well in exams. Refer to Introduction to Three Dimensional Geometry Class 11 MCQs Quiz Questions with Answers here along with a detailed explanation.

Introduction to Three Dimensional Geometry Class 11 MCQs Questions with Answers

MCQ Questions for Class 11 Maths Chapter 12 Introduction to Three Dimensional Geometry with Answers

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1. In a three dimensional space, the equation 3x – 4y = 0 represents

 
 
 
 

2. The equation xy = 0 in three dimensional space represents

 
 
 
 

3. If α, β, γ are the angles made by a half ray of a line respectively with positive directions of X-axis Y-axis and Z-axis, then sin² α + sin² β + sin² γ =

 
 
 
 

4. The coordinates of the point where the line through (5, 1, 6) and (3, 4, 1) crosses the YZ plane is

 
 
 
 

5. The points on the y- axis which are at a distance of 3 units from the point (2, 3, -1) is

 
 
 
 

6. The maximum distance between points (3sin θ, 0, 0) and (4cos θ, 0, 0) is

 
 
 
 

7. A vector r is equally inclined with the coordinate axes. If the tip of r is in the positive octant and |r| = 6, then r is

 
 
 
 

8. The angle between the vectors with direction ratios are 4, -3, 5 and 3, 4, 5 is

 
 
 
 

9. A and B be the points (3, 4, 5) and (-1, -3, -7), respectively, the equation of the set of points P such that PA2 + PB2 = k2, where k is a constant will

 
 
 
 

10. If P(x, y, z) is a point on the line segment joining Q(2, 2, 4) and R(3, 5, 6) such that the projections of OP on the axes are 13/5, 19/5, 26/5 respectively, then P divides QR in the ration

 
 
 
 

11. The locus represented by xy + yz = 0 is

 
 
 
 

12. The distance of the point (3, 4, 5) from X- axis is 

 
 
 
 

13. The locus of a point P which moves such that PA2 – PB2 = 2k2 where A and B are (3, 4, 5) and (–1, 3, –7) respectively is

 
 
 
 

14. The equation of the plane passing through the point (1, – 3, –2) and perpendicular to planes x + 2y + 2z = 5 and 3x + 3y + 2z = 8, is

 
 
 
 

15. The image of the point P(1, 3, 4) in the plane 2x – y + z = 0 is

 
 
 
 

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